Metamath Proof Explorer


Theorem esumeq12dvaf

Description: Equality deduction for extended sum. (Contributed by Thierry Arnoux, 26-Mar-2017)

Ref Expression
Hypotheses esumeq12dvaf.1 ⊢ Ⅎ k φ
esumeq12dvaf.2 ⊢ φ → A = B
esumeq12dvaf.3 ⊢ φ ∧ k ∈ A → C = D
Assertion esumeq12dvaf ⊢ φ → ∑ * k ∈ A C = ∑ * k ∈ B D

Proof

Step Hyp Ref Expression
1 esumeq12dvaf.1 ⊢ Ⅎ k φ
2 esumeq12dvaf.2 ⊢ φ → A = B
3 esumeq12dvaf.3 ⊢ φ ∧ k ∈ A → C = D
4 1 2 alrimi ⊢ φ → ∀ k A = B
5 3 ex ⊢ φ → k ∈ A → C = D
6 1 5 ralrimi ⊢ φ → ∀ k ∈ A C = D
7 mpteq12f ⊢ ∀ k A = B ∧ ∀ k ∈ A C = D → k ∈ A ⟼ C = k ∈ B ⟼ D
8 4 6 7 syl2anc ⊢ φ → k ∈ A ⟼ C = k ∈ B ⟼ D
9 8 oveq2d ⊢ φ → ℝ 𝑠 * ↾ 𝑠 0 +∞ tsums k ∈ A ⟼ C = ℝ 𝑠 * ↾ 𝑠 0 +∞ tsums k ∈ B ⟼ D
10 9 unieqd ⊢ φ → ⋃ ℝ 𝑠 * ↾ 𝑠 0 +∞ tsums k ∈ A ⟼ C = ⋃ ℝ 𝑠 * ↾ 𝑠 0 +∞ tsums k ∈ B ⟼ D
11 df-esum ⊢ ∑ * k ∈ A C = ⋃ ℝ 𝑠 * ↾ 𝑠 0 +∞ tsums k ∈ A ⟼ C
12 df-esum ⊢ ∑ * k ∈ B D = ⋃ ℝ 𝑠 * ↾ 𝑠 0 +∞ tsums k ∈ B ⟼ D
13 10 11 12 3eqtr4g ⊢ φ → ∑ * k ∈ A C = ∑ * k ∈ B D