Metamath Proof Explorer


Theorem esumeq2d

Description: Equality deduction for extended sum. (Contributed by Thierry Arnoux, 21-Sep-2016)

Ref Expression
Hypotheses esumeq2d.0 ⊢ Ⅎ k φ
esumeq2d.1 ⊢ φ → ∀ k ∈ A B = C
Assertion esumeq2d ⊢ φ → ∑ * k ∈ A B = ∑ * k ∈ A C

Proof

Step Hyp Ref Expression
1 esumeq2d.0 ⊢ Ⅎ k φ
2 esumeq2d.1 ⊢ φ → ∀ k ∈ A B = C
3 eqidd ⊢ φ → A = A
4 2 r19.21bi ⊢ φ ∧ k ∈ A → B = C
5 1 3 4 esumeq12dvaf ⊢ φ → ∑ * k ∈ A B = ∑ * k ∈ A C