Metamath Proof Explorer


Theorem esumeq2d

Description: Equality deduction for extended sum. (Contributed by Thierry Arnoux, 21-Sep-2016)

Ref Expression
Hypotheses esumeq2d.0 ⊢ Ⅎ 𝑘 𝜑
esumeq2d.1 ⊢ ( 𝜑 → ∀ 𝑘 ∈ 𝐴 𝐵 = 𝐶 )
Assertion esumeq2d ( 𝜑 → Σ* 𝑘 ∈ 𝐴 𝐵 = Σ* 𝑘 ∈ 𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 esumeq2d.0 ⊢ Ⅎ 𝑘 𝜑
2 esumeq2d.1 ⊢ ( 𝜑 → ∀ 𝑘 ∈ 𝐴 𝐵 = 𝐶 )
3 eqidd ⊢ ( 𝜑 → 𝐴 = 𝐴 )
4 2 r19.21bi ⊢ ( ( 𝜑 ∧ 𝑘 ∈ 𝐴 ) → 𝐵 = 𝐶 )
5 1 3 4 esumeq12dvaf ⊢ ( 𝜑 → Σ* 𝑘 ∈ 𝐴 𝐵 = Σ* 𝑘 ∈ 𝐴 𝐶 )