Metamath Proof Explorer


Theorem f1oen2g

Description: The domain and range of a one-to-one, onto function are equinumerous. This variation of f1oeng does not require the Axiom of Replacement. (Contributed by Mario Carneiro, 10-Sep-2015)

Ref Expression
Assertion f1oen2g ⊢ A ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 onto B → A ≈ B

Proof

Step Hyp Ref Expression
1 f1of ⊢ F : A ⟶ 1-1 onto B → F : A ⟶ B
2 fex2 ⊢ F : A ⟶ B ∧ A ∈ V ∧ B ∈ W → F ∈ V
3 1 2 syl3an1 ⊢ F : A ⟶ 1-1 onto B ∧ A ∈ V ∧ B ∈ W → F ∈ V
4 3 3coml ⊢ A ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 onto B → F ∈ V
5 simp3 ⊢ A ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 onto B → F : A ⟶ 1-1 onto B
6 f1oen3g ⊢ F ∈ V ∧ F : A ⟶ 1-1 onto B → A ≈ B
7 4 5 6 syl2anc ⊢ A ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 onto B → A ≈ B