Metamath Proof Explorer


Theorem f1dom2g

Description: The domain of a one-to-one function is dominated by its codomain. This variation of f1domg does not require the Axiom of Replacement. (Contributed by Mario Carneiro, 24-Jun-2015) (Proof shortened by BTernaryTau, 25-Sep-2024)

Ref Expression
Assertion f1dom2g ⊢ A ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → A ≼ B

Proof

Step Hyp Ref Expression
1 f1f ⊢ F : A ⟶ 1-1 B → F : A ⟶ B
2 fex2 ⊢ F : A ⟶ B ∧ A ∈ V ∧ B ∈ W → F ∈ V
3 1 2 syl3an1 ⊢ F : A ⟶ 1-1 B ∧ A ∈ V ∧ B ∈ W → F ∈ V
4 3 3coml ⊢ A ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → F ∈ V
5 f1dom3g ⊢ F ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → A ≼ B
6 4 5 syld3an1 ⊢ A ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → A ≼ B