Metamath Proof Explorer


Theorem f1dom3g

Description: The domain of a one-to-one set function is dominated by its codomain when the latter is a set. This variation of f1domg does not require the Axiom of Replacement nor the Axiom of Power Sets. (Contributed by BTernaryTau, 9-Sep-2024)

Ref Expression
Assertion f1dom3g ⊢ F ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → A ≼ B

Proof

Step Hyp Ref Expression
1 f1eq1 ⊢ f = F → f : A ⟶ 1-1 B ↔ F : A ⟶ 1-1 B
2 1 spcegv ⊢ F ∈ V → F : A ⟶ 1-1 B → ∃ f f : A ⟶ 1-1 B
3 2 imp ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → ∃ f f : A ⟶ 1-1 B
4 3 3adant2 ⊢ F ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → ∃ f f : A ⟶ 1-1 B
5 brdomg ⊢ B ∈ W → A ≼ B ↔ ∃ f f : A ⟶ 1-1 B
6 5 3ad2ant2 ⊢ F ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → A ≼ B ↔ ∃ f f : A ⟶ 1-1 B
7 4 6 mpbird ⊢ F ∈ V ∧ B ∈ W ∧ F : A ⟶ 1-1 B → A ≼ B