Metamath Proof Explorer


Theorem f1dom2g

Description: The domain of a one-to-one function is dominated by its codomain. This variation of f1domg does not require the Axiom of Replacement. (Contributed by Mario Carneiro, 24-Jun-2015) (Proof shortened by BTernaryTau, 25-Sep-2024)

Ref Expression
Assertion f1dom2g ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐹 : 𝐴 –1-1→ 𝐵 ) → 𝐴 ≼ 𝐵 )

Proof

Step Hyp Ref Expression
1 f1f ⊢ ( 𝐹 : 𝐴 –1-1→ 𝐵 → 𝐹 : 𝐴 ⟶ 𝐵 )
2 fex2 ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → 𝐹 ∈ V )
3 1 2 syl3an1 ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → 𝐹 ∈ V )
4 3 3coml ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐹 : 𝐴 –1-1→ 𝐵 ) → 𝐹 ∈ V )
5 f1dom3g ⊢ ( ( 𝐹 ∈ V ∧ 𝐵 ∈ 𝑊 ∧ 𝐹 : 𝐴 –1-1→ 𝐵 ) → 𝐴 ≼ 𝐵 )
6 4 5 syld3an1 ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐹 : 𝐴 –1-1→ 𝐵 ) → 𝐴 ≼ 𝐵 )