Metamath Proof Explorer


Theorem f1omo

Description: There is at most one element in the function value of a constant function whose output is 1o . (An artifact of our function value definition.) Proof could be significantly shortened by fvconstdomi assuming ax-un (see f1omoALT ). (Contributed by Zhi Wang, 19-Sep-2024) (Proof shortened by SN, 24-Nov-2025)

Ref Expression
Hypothesis f1omo.1 ⊢ φ → F = A × 1 𝑜
Assertion f1omo ⊢ φ → ∃* y y ∈ F ⁡ X

Proof

Step Hyp Ref Expression
1 f1omo.1 ⊢ φ → F = A × 1 𝑜
2 1oex ⊢ 1 𝑜 ∈ V
3 eqid ⊢ A × 1 𝑜 ⁡ X = A × 1 𝑜 ⁡ X
4 2 3 fvconst0ci ⊢ A × 1 𝑜 ⁡ X = ∅ ∨ A × 1 𝑜 ⁡ X = 1 𝑜
5 mo0 ⊢ A × 1 𝑜 ⁡ X = ∅ → ∃* y y ∈ A × 1 𝑜 ⁡ X
6 df1o2 ⊢ 1 𝑜 = ∅
7 6 eqeq2i ⊢ A × 1 𝑜 ⁡ X = 1 𝑜 ↔ A × 1 𝑜 ⁡ X = ∅
8 mosn ⊢ A × 1 𝑜 ⁡ X = ∅ → ∃* y y ∈ A × 1 𝑜 ⁡ X
9 7 8 sylbi ⊢ A × 1 𝑜 ⁡ X = 1 𝑜 → ∃* y y ∈ A × 1 𝑜 ⁡ X
10 5 9 jaoi ⊢ A × 1 𝑜 ⁡ X = ∅ ∨ A × 1 𝑜 ⁡ X = 1 𝑜 → ∃* y y ∈ A × 1 𝑜 ⁡ X
11 4 10 ax-mp ⊢ ∃* y y ∈ A × 1 𝑜 ⁡ X
12 1 fveq1d ⊢ φ → F ⁡ X = A × 1 𝑜 ⁡ X
13 12 eleq2d ⊢ φ → y ∈ F ⁡ X ↔ y ∈ A × 1 𝑜 ⁡ X
14 13 mobidv ⊢ φ → ∃* y y ∈ F ⁡ X ↔ ∃* y y ∈ A × 1 𝑜 ⁡ X
15 11 14 mpbiri ⊢ φ → ∃* y y ∈ F ⁡ X