Metamath Proof Explorer


Theorem f1ss

Description: A function that is one-to-one is also one-to-one on some superset of its codomain. (Contributed by Mario Carneiro, 12-Jan-2013)

Ref Expression
Assertion f1ss ⊢ F : A ⟶ 1-1 B ∧ B ⊆ C → F : A ⟶ 1-1 C

Proof

Step Hyp Ref Expression
1 f1f ⊢ F : A ⟶ 1-1 B → F : A ⟶ B
2 fss ⊢ F : A ⟶ B ∧ B ⊆ C → F : A ⟶ C
3 1 2 sylan ⊢ F : A ⟶ 1-1 B ∧ B ⊆ C → F : A ⟶ C
4 df-f1 ⊢ F : A ⟶ 1-1 B ↔ F : A ⟶ B ∧ Fun ⁡ F -1
5 4 simprbi ⊢ F : A ⟶ 1-1 B → Fun ⁡ F -1
6 5 adantr ⊢ F : A ⟶ 1-1 B ∧ B ⊆ C → Fun ⁡ F -1
7 df-f1 ⊢ F : A ⟶ 1-1 C ↔ F : A ⟶ C ∧ Fun ⁡ F -1
8 3 6 7 sylanbrc ⊢ F : A ⟶ 1-1 B ∧ B ⊆ C → F : A ⟶ 1-1 C