Metamath Proof Explorer


Theorem f1ss

Description: A function that is one-to-one is also one-to-one on some superset of its codomain. (Contributed by Mario Carneiro, 12-Jan-2013)

Ref Expression
Assertion f1ss ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐹 : 𝐴 –1-1→ 𝐶 )

Proof

Step Hyp Ref Expression
1 f1f ⊢ ( 𝐹 : 𝐴 –1-1→ 𝐵 → 𝐹 : 𝐴 ⟶ 𝐵 )
2 fss ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐹 : 𝐴 ⟶ 𝐶 )
3 1 2 sylan ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐹 : 𝐴 ⟶ 𝐶 )
4 df-f1 ⊢ ( 𝐹 : 𝐴 –1-1→ 𝐵 ↔ ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ Fun ◡ 𝐹 ) )
5 4 simprbi ⊢ ( 𝐹 : 𝐴 –1-1→ 𝐵 → Fun ◡ 𝐹 )
6 5 adantr ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → Fun ◡ 𝐹 )
7 df-f1 ⊢ ( 𝐹 : 𝐴 –1-1→ 𝐶 ↔ ( 𝐹 : 𝐴 ⟶ 𝐶 ∧ Fun ◡ 𝐹 ) )
8 3 6 7 sylanbrc ⊢ ( ( 𝐹 : 𝐴 –1-1→ 𝐵 ∧ 𝐵 ⊆ 𝐶 ) → 𝐹 : 𝐴 –1-1→ 𝐶 )