Metamath Proof Explorer


Theorem fneer

Description: Fineness intersected with its converse is an equivalence relation. (Contributed by Jeff Hankins, 6-Oct-2009) (Revised by Mario Carneiro, 11-Sep-2015)

Ref Expression
Hypothesis fneval.1 ⊢ ∼ ˙ = Fne ∩ Fne -1
Assertion fneer ⊢ ∼ ˙ Er V

Proof

Step Hyp Ref Expression
1 fneval.1 ⊢ ∼ ˙ = Fne ∩ Fne -1
2 fveq2 ⊢ x = y → topGen ⁡ x = topGen ⁡ y
3 inss1 ⊢ Fne ∩ Fne -1 ⊆ Fne
4 1 3 eqsstri ⊢ ∼ ˙ ⊆ Fne
5 fnerel ⊢ Rel ⁡ Fne
6 relss ⊢ ∼ ˙ ⊆ Fne → Rel ⁡ Fne → Rel ⁡ ∼ ˙
7 4 5 6 mp2 ⊢ Rel ⁡ ∼ ˙
8 dfrel4v ⊢ Rel ⁡ ∼ ˙ ↔ ∼ ˙ = x y | x ∼ ˙ y
9 7 8 mpbi ⊢ ∼ ˙ = x y | x ∼ ˙ y
10 1 fneval ⊢ x ∈ V ∧ y ∈ V → x ∼ ˙ y ↔ topGen ⁡ x = topGen ⁡ y
11 10 el2v ⊢ x ∼ ˙ y ↔ topGen ⁡ x = topGen ⁡ y
12 11 opabbii ⊢ x y | x ∼ ˙ y = x y | topGen ⁡ x = topGen ⁡ y
13 9 12 eqtri ⊢ ∼ ˙ = x y | topGen ⁡ x = topGen ⁡ y
14 2 13 eqer ⊢ ∼ ˙ Er V