Metamath Proof Explorer


Theorem fnessex

Description: If B is finer than A and S is an element of A , every point in S is an element of a subset of S which is in B . (Contributed by Jeff Hankins, 28-Sep-2009)

Ref Expression
Assertion fnessex ⊢ A Fne B ∧ S ∈ A ∧ P ∈ S → ∃ x ∈ B P ∈ x ∧ x ⊆ S

Proof

Step Hyp Ref Expression
1 fnetg ⊢ A Fne B → A ⊆ topGen ⁡ B
2 1 sselda ⊢ A Fne B ∧ S ∈ A → S ∈ topGen ⁡ B
3 tg2 ⊢ S ∈ topGen ⁡ B ∧ P ∈ S → ∃ x ∈ B P ∈ x ∧ x ⊆ S
4 2 3 stoic3 ⊢ A Fne B ∧ S ∈ A ∧ P ∈ S → ∃ x ∈ B P ∈ x ∧ x ⊆ S