Metamath Proof Explorer


Theorem fprodcllem

Description: Finite product closure lemma. (Contributed by Scott Fenton, 14-Dec-2017)

Ref Expression
Hypotheses fprodcllem.1 ⊢ φ → S ⊆ ℂ
fprodcllem.2 ⊢ φ ∧ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
fprodcllem.3 ⊢ φ → A ∈ Fin
fprodcllem.4 ⊢ φ ∧ k ∈ A → B ∈ S
fprodcllem.5 ⊢ φ → 1 ∈ S
Assertion fprodcllem ⊢ φ → ∏ k ∈ A B ∈ S

Proof

Step Hyp Ref Expression
1 fprodcllem.1 ⊢ φ → S ⊆ ℂ
2 fprodcllem.2 ⊢ φ ∧ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
3 fprodcllem.3 ⊢ φ → A ∈ Fin
4 fprodcllem.4 ⊢ φ ∧ k ∈ A → B ∈ S
5 fprodcllem.5 ⊢ φ → 1 ∈ S
6 prodeq1 ⊢ A = ∅ → ∏ k ∈ A B = ∏ k ∈ ∅ B
7 prod0 ⊢ ∏ k ∈ ∅ B = 1
8 6 7 eqtrdi ⊢ A = ∅ → ∏ k ∈ A B = 1
9 8 adantl ⊢ φ ∧ A = ∅ → ∏ k ∈ A B = 1
10 5 adantr ⊢ φ ∧ A = ∅ → 1 ∈ S
11 9 10 eqeltrd ⊢ φ ∧ A = ∅ → ∏ k ∈ A B ∈ S
12 1 adantr ⊢ φ ∧ A ≠ ∅ → S ⊆ ℂ
13 2 adantlr ⊢ φ ∧ A ≠ ∅ ∧ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
14 3 adantr ⊢ φ ∧ A ≠ ∅ → A ∈ Fin
15 4 adantlr ⊢ φ ∧ A ≠ ∅ ∧ k ∈ A → B ∈ S
16 simpr ⊢ φ ∧ A ≠ ∅ → A ≠ ∅
17 12 13 14 15 16 fprodcl2lem ⊢ φ ∧ A ≠ ∅ → ∏ k ∈ A B ∈ S
18 11 17 pm2.61dane ⊢ φ → ∏ k ∈ A B ∈ S