Metamath Proof Explorer


Theorem frege55c

Description: Proposition 55 of Frege1879 p. 50. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege55c ⊢ x = A → A = x

Proof

Step Hyp Ref Expression
1 vex ⊢ x ∈ V
2 1 frege54cor1c ⊢ [˙x / y]˙ y = x
3 frege53c ⊢ [˙x / y]˙ y = x → x = A → [˙A / y]˙ y = x
4 2 3 ax-mp ⊢ x = A → [˙A / y]˙ y = x
5 df-sbc ⊢ [˙A / y]˙ y = x ↔ A ∈ y | y = x
6 clelab ⊢ A ∈ y | y = x ↔ ∃ y y = A ∧ y = x
7 5 6 bitri ⊢ [˙A / y]˙ y = x ↔ ∃ y y = A ∧ y = x
8 eqtr2 ⊢ y = A ∧ y = x → A = x
9 8 exlimiv ⊢ ∃ y y = A ∧ y = x → A = x
10 7 9 sylbi ⊢ [˙A / y]˙ y = x → A = x
11 4 10 syl ⊢ x = A → A = x