Metamath Proof Explorer


Theorem frege55c

Description: Proposition 55 of Frege1879 p. 50. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion frege55c ( 𝑥 = 𝐴 → 𝐴 = 𝑥 )

Proof

Step Hyp Ref Expression
1 vex ⊢ 𝑥 ∈ V
2 1 frege54cor1c ⊢ [ 𝑥 / 𝑦 ] 𝑦 = 𝑥
3 frege53c ⊢ ( [ 𝑥 / 𝑦 ] 𝑦 = 𝑥 → ( 𝑥 = 𝐴 → [ 𝐴 / 𝑦 ] 𝑦 = 𝑥 ) )
4 2 3 ax-mp ⊢ ( 𝑥 = 𝐴 → [ 𝐴 / 𝑦 ] 𝑦 = 𝑥 )
5 df-sbc ⊢ ( [ 𝐴 / 𝑦 ] 𝑦 = 𝑥 ↔ 𝐴 ∈ { 𝑦 ∣ 𝑦 = 𝑥 } )
6 clelab ⊢ ( 𝐴 ∈ { 𝑦 ∣ 𝑦 = 𝑥 } ↔ ∃ 𝑦 ( 𝑦 = 𝐴 ∧ 𝑦 = 𝑥 ) )
7 5 6 bitri ⊢ ( [ 𝐴 / 𝑦 ] 𝑦 = 𝑥 ↔ ∃ 𝑦 ( 𝑦 = 𝐴 ∧ 𝑦 = 𝑥 ) )
8 eqtr2 ⊢ ( ( 𝑦 = 𝐴 ∧ 𝑦 = 𝑥 ) → 𝐴 = 𝑥 )
9 8 exlimiv ⊢ ( ∃ 𝑦 ( 𝑦 = 𝐴 ∧ 𝑦 = 𝑥 ) → 𝐴 = 𝑥 )
10 7 9 sylbi ⊢ ( [ 𝐴 / 𝑦 ] 𝑦 = 𝑥 → 𝐴 = 𝑥 )
11 4 10 syl ⊢ ( 𝑥 = 𝐴 → 𝐴 = 𝑥 )