Metamath Proof Explorer


Theorem frege56c

Description: Lemma for frege57c . Proposition 56 of Frege1879 p. 50. (Contributed by RP, 24-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis frege56c.b ⊢ 𝐵 ∈ 𝐶
Assertion frege56c ( ( 𝐴 = 𝐵 → ( [ 𝐴 / 𝑥 ] 𝜑 → [ 𝐵 / 𝑥 ] 𝜑 ) ) → ( 𝐵 = 𝐴 → ( [ 𝐴 / 𝑥 ] 𝜑 → [ 𝐵 / 𝑥 ] 𝜑 ) ) )

Proof

Step Hyp Ref Expression
1 frege56c.b ⊢ 𝐵 ∈ 𝐶
2 1 frege54cor1c ⊢ [ 𝐵 / 𝑥 ] 𝑥 = 𝐵
3 frege53c ⊢ ( [ 𝐵 / 𝑥 ] 𝑥 = 𝐵 → ( 𝐵 = 𝐴 → [ 𝐴 / 𝑥 ] 𝑥 = 𝐵 ) )
4 2 3 ax-mp ⊢ ( 𝐵 = 𝐴 → [ 𝐴 / 𝑥 ] 𝑥 = 𝐵 )
5 frege55lem1c ⊢ ( ( 𝐵 = 𝐴 → [ 𝐴 / 𝑥 ] 𝑥 = 𝐵 ) → ( 𝐵 = 𝐴 → 𝐴 = 𝐵 ) )
6 4 5 ax-mp ⊢ ( 𝐵 = 𝐴 → 𝐴 = 𝐵 )
7 frege9 ⊢ ( ( 𝐵 = 𝐴 → 𝐴 = 𝐵 ) → ( ( 𝐴 = 𝐵 → ( [ 𝐴 / 𝑥 ] 𝜑 → [ 𝐵 / 𝑥 ] 𝜑 ) ) → ( 𝐵 = 𝐴 → ( [ 𝐴 / 𝑥 ] 𝜑 → [ 𝐵 / 𝑥 ] 𝜑 ) ) ) )
8 6 7 ax-mp ⊢ ( ( 𝐴 = 𝐵 → ( [ 𝐴 / 𝑥 ] 𝜑 → [ 𝐵 / 𝑥 ] 𝜑 ) ) → ( 𝐵 = 𝐴 → ( [ 𝐴 / 𝑥 ] 𝜑 → [ 𝐵 / 𝑥 ] 𝜑 ) ) )