Metamath Proof Explorer


Theorem funALTVss

Description: Subclass theorem for function. (Contributed by NM, 16-Aug-1994) (Proof shortened by Mario Carneiro, 24-Jun-2014) (Revised by Peter Mazsa, 22-Sep-2021)

Ref Expression
Assertion funALTVss ABFunALTVBFunALTVA

Proof

Step Hyp Ref Expression
1 cossss ABAB
2 sstr2 ABBIAI
3 1 2 syl ABBIAI
4 relss ABRelBRelA
5 3 4 anim12d ABBIRelBAIRelA
6 dffunALTV2 FunALTVBBIRelB
7 dffunALTV2 FunALTVAAIRelA
8 5 6 7 3imtr4g ABFunALTVBFunALTVA