Metamath Proof Explorer


Theorem fv1arycl

Description: Closure of a unary (endo)function. (Contributed by AV, 18-May-2024)

Ref Expression
Assertion fv1arycl ⊢ G ∈ 1 -aryF X ∧ A ∈ X → G ⁡ 0 A ∈ X

Proof

Step Hyp Ref Expression
1 eqid ⊢ 0 ..^ 1 = 0 ..^ 1
2 1 naryrcl ⊢ G ∈ 1 -aryF X → 1 ∈ ℕ 0 ∧ X ∈ V
3 1aryfvalel ⊢ X ∈ V → G ∈ 1 -aryF X ↔ G : X 0 ⟶ X
4 simp2 ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → G : X 0 ⟶ X
5 c0ex ⊢ 0 ∈ V
6 5 a1i ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → 0 ∈ V
7 simp3 ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → A ∈ X
8 6 7 fsnd ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → 0 A : 0 ⟶ X
9 simp1 ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → X ∈ V
10 snex ⊢ 0 ∈ V
11 10 a1i ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → 0 ∈ V
12 9 11 elmapd ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → 0 A ∈ X 0 ↔ 0 A : 0 ⟶ X
13 8 12 mpbird ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → 0 A ∈ X 0
14 4 13 ffvelcdmd ⊢ X ∈ V ∧ G : X 0 ⟶ X ∧ A ∈ X → G ⁡ 0 A ∈ X
15 14 3exp ⊢ X ∈ V → G : X 0 ⟶ X → A ∈ X → G ⁡ 0 A ∈ X
16 3 15 sylbid ⊢ X ∈ V → G ∈ 1 -aryF X → A ∈ X → G ⁡ 0 A ∈ X
17 16 adantl ⊢ 1 ∈ ℕ 0 ∧ X ∈ V → G ∈ 1 -aryF X → A ∈ X → G ⁡ 0 A ∈ X
18 2 17 mpcom ⊢ G ∈ 1 -aryF X → A ∈ X → G ⁡ 0 A ∈ X
19 18 imp ⊢ G ∈ 1 -aryF X ∧ A ∈ X → G ⁡ 0 A ∈ X