Metamath Proof Explorer


Theorem gpg3kgrtriexlem3

Description: Lemma 3 for gpg3kgrtriex . (Contributed by AV, 1-Oct-2025)

Ref Expression
Hypothesis gpg3kgrtriex.n ⊢ N = 3 ⁢ K
Assertion gpg3kgrtriexlem3 ⊢ K ∈ ℕ → N ∈ ℤ ≥ 3

Proof

Step Hyp Ref Expression
1 gpg3kgrtriex.n ⊢ N = 3 ⁢ K
2 3z ⊢ 3 ∈ ℤ
3 2 a1i ⊢ K ∈ ℕ → 3 ∈ ℤ
4 nnz ⊢ K ∈ ℕ → K ∈ ℤ
5 3 4 zmulcld ⊢ K ∈ ℕ → 3 ⁢ K ∈ ℤ
6 3t1e3 ⊢ 3 ⋅ 1 = 3
7 nnge1 ⊢ K ∈ ℕ → 1 ≤ K
8 1re ⊢ 1 ∈ ℝ
9 nnre ⊢ K ∈ ℕ → K ∈ ℝ
10 3re ⊢ 3 ∈ ℝ
11 3pos ⊢ 0 < 3
12 10 11 pm3.2i ⊢ 3 ∈ ℝ ∧ 0 < 3
13 12 a1i ⊢ K ∈ ℕ → 3 ∈ ℝ ∧ 0 < 3
14 lemul2 ⊢ 1 ∈ ℝ ∧ K ∈ ℝ ∧ 3 ∈ ℝ ∧ 0 < 3 → 1 ≤ K ↔ 3 ⋅ 1 ≤ 3 ⁢ K
15 8 9 13 14 mp3an2i ⊢ K ∈ ℕ → 1 ≤ K ↔ 3 ⋅ 1 ≤ 3 ⁢ K
16 7 15 mpbid ⊢ K ∈ ℕ → 3 ⋅ 1 ≤ 3 ⁢ K
17 6 16 eqbrtrrid ⊢ K ∈ ℕ → 3 ≤ 3 ⁢ K
18 eluz2 ⊢ 3 ⁢ K ∈ ℤ ≥ 3 ↔ 3 ∈ ℤ ∧ 3 ⁢ K ∈ ℤ ∧ 3 ≤ 3 ⁢ K
19 3 5 17 18 syl3anbrc ⊢ K ∈ ℕ → 3 ⁢ K ∈ ℤ ≥ 3
20 1 19 eqeltrid ⊢ K ∈ ℕ → N ∈ ℤ ≥ 3