Metamath Proof Explorer


Theorem gruscottcld

Description: If a Grothendieck universe contains an element of a Scott's trick set, it contains the Scott's trick set. (Contributed by Rohan Ridenour, 11-Aug-2023)

Ref Expression
Hypotheses gruscottcld.1 ⊢ φ → G ∈ Univ
gruscottcld.2 ⊢ φ → B ∈ G
gruscottcld.3 ⊢ φ → B ∈ Scott A
Assertion gruscottcld ⊢ φ → Scott A ∈ G

Proof

Step Hyp Ref Expression
1 gruscottcld.1 ⊢ φ → G ∈ Univ
2 gruscottcld.2 ⊢ φ → B ∈ G
3 gruscottcld.3 ⊢ φ → B ∈ Scott A
4 3 scottrankd ⊢ φ → rank ⁡ Scott A = suc ⁡ rank ⁡ B
5 1 2 grurankcld ⊢ φ → rank ⁡ B ∈ G
6 1 5 grusucd ⊢ φ → suc ⁡ rank ⁡ B ∈ G
7 4 6 eqeltrd ⊢ φ → rank ⁡ Scott A ∈ G
8 scottex ⊢ Scott A ∈ V
9 8 a1i ⊢ φ → Scott A ∈ V
10 1 7 9 grurankrcld ⊢ φ → Scott A ∈ G