Metamath Proof Explorer


Theorem hdmap1valc

Description: Connect the value of the preliminary map from vectors to functionals I to the hypothesis L used by earlier theorems. Note: the X e. ( V \ { .0. } ) hypothesis could be the more general X e. V but the former will be easier to use. TODO: use the I function directly in those theorems, so this theorem becomes unnecessary? TODO: The hdmap1cbv is probably unnecessary, but it would mean different $d's later on. (Contributed by NM, 15-May-2015)

Ref Expression
Hypotheses hdmap1valc.h ⊢ H = LHyp ⁡ K
hdmap1valc.u ⊢ U = DVecH ⁡ K ⁡ W
hdmap1valc.v ⊢ V = Base U
hdmap1valc.s ⊢ - ˙ = - U
hdmap1valc.o ⊢ 0 ˙ = 0 U
hdmap1valc.n ⊢ N = LSpan ⁡ U
hdmap1valc.c ⊢ C = LCDual ⁡ K ⁡ W
hdmap1valc.d ⊢ D = Base C
hdmap1valc.r ⊢ R = - C
hdmap1valc.q ⊢ Q = 0 C
hdmap1valc.j ⊢ J = LSpan ⁡ C
hdmap1valc.m ⊢ M = mapd ⁡ K ⁡ W
hdmap1valc.i ⊢ I = HDMap1 ⁡ K ⁡ W
hdmap1valc.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmap1valc.x ⊢ φ → X ∈ V ∖ 0 ˙
hdmap1valc.f ⊢ φ → F ∈ D
hdmap1valc.y ⊢ φ → Y ∈ V
hdmap1valc.l ⊢ L = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
Assertion hdmap1valc ⊢ φ → I ⁡ X F Y = L ⁡ X F Y

Proof

Step Hyp Ref Expression
1 hdmap1valc.h ⊢ H = LHyp ⁡ K
2 hdmap1valc.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmap1valc.v ⊢ V = Base U
4 hdmap1valc.s ⊢ - ˙ = - U
5 hdmap1valc.o ⊢ 0 ˙ = 0 U
6 hdmap1valc.n ⊢ N = LSpan ⁡ U
7 hdmap1valc.c ⊢ C = LCDual ⁡ K ⁡ W
8 hdmap1valc.d ⊢ D = Base C
9 hdmap1valc.r ⊢ R = - C
10 hdmap1valc.q ⊢ Q = 0 C
11 hdmap1valc.j ⊢ J = LSpan ⁡ C
12 hdmap1valc.m ⊢ M = mapd ⁡ K ⁡ W
13 hdmap1valc.i ⊢ I = HDMap1 ⁡ K ⁡ W
14 hdmap1valc.k ⊢ φ → K ∈ HL ∧ W ∈ H
15 hdmap1valc.x ⊢ φ → X ∈ V ∖ 0 ˙
16 hdmap1valc.f ⊢ φ → F ∈ D
17 hdmap1valc.y ⊢ φ → Y ∈ V
18 hdmap1valc.l ⊢ L = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
19 15 eldifad ⊢ φ → X ∈ V
20 1 2 3 4 5 6 7 8 9 10 11 12 13 14 19 16 17 hdmap1val ⊢ φ → I ⁡ X F Y = if Y = 0 ˙ Q ι g ∈ D | M ⁡ N ⁡ Y = J ⁡ g ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R g
21 18 hdmap1cbv ⊢ L = w ∈ V ⟼ if 2 nd ⁡ w = 0 ˙ Q ι g ∈ D | M ⁡ N ⁡ 2 nd ⁡ w = J ⁡ g ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ w - ˙ 2 nd ⁡ w = J ⁡ 2 nd ⁡ 1 st ⁡ w R g
22 10 21 19 16 17 mapdhval ⊢ φ → L ⁡ X F Y = if Y = 0 ˙ Q ι g ∈ D | M ⁡ N ⁡ Y = J ⁡ g ∧ M ⁡ N ⁡ X - ˙ Y = J ⁡ F R g
23 20 22 eqtr4d ⊢ φ → I ⁡ X F Y = L ⁡ X F Y