Metamath Proof Explorer


Theorem hdmap1valc

Description: Connect the value of the preliminary map from vectors to functionals I to the hypothesis L used by earlier theorems. Note: the X e. ( V \ { .0. } ) hypothesis could be the more general X e. V but the former will be easier to use. TODO: use the I function directly in those theorems, so this theorem becomes unnecessary? TODO: The hdmap1cbv is probably unnecessary, but it would mean different $d's later on. (Contributed by NM, 15-May-2015)

Ref Expression
Hypotheses hdmap1valc.h H = LHyp K
hdmap1valc.u U = DVecH K W
hdmap1valc.v V = Base U
hdmap1valc.s - ˙ = - U
hdmap1valc.o 0 ˙ = 0 U
hdmap1valc.n N = LSpan U
hdmap1valc.c C = LCDual K W
hdmap1valc.d D = Base C
hdmap1valc.r R = - C
hdmap1valc.q Q = 0 C
hdmap1valc.j J = LSpan C
hdmap1valc.m M = mapd K W
hdmap1valc.i I = HDMap1 K W
hdmap1valc.k φ K HL W H
hdmap1valc.x φ X V 0 ˙
hdmap1valc.f φ F D
hdmap1valc.y φ Y V
hdmap1valc.l L = x V if 2 nd x = 0 ˙ Q ι h D | M N 2 nd x = J h M N 1 st 1 st x - ˙ 2 nd x = J 2 nd 1 st x R h
Assertion hdmap1valc φ I X F Y = L X F Y

Proof

Step Hyp Ref Expression
1 hdmap1valc.h H = LHyp K
2 hdmap1valc.u U = DVecH K W
3 hdmap1valc.v V = Base U
4 hdmap1valc.s - ˙ = - U
5 hdmap1valc.o 0 ˙ = 0 U
6 hdmap1valc.n N = LSpan U
7 hdmap1valc.c C = LCDual K W
8 hdmap1valc.d D = Base C
9 hdmap1valc.r R = - C
10 hdmap1valc.q Q = 0 C
11 hdmap1valc.j J = LSpan C
12 hdmap1valc.m M = mapd K W
13 hdmap1valc.i I = HDMap1 K W
14 hdmap1valc.k φ K HL W H
15 hdmap1valc.x φ X V 0 ˙
16 hdmap1valc.f φ F D
17 hdmap1valc.y φ Y V
18 hdmap1valc.l L = x V if 2 nd x = 0 ˙ Q ι h D | M N 2 nd x = J h M N 1 st 1 st x - ˙ 2 nd x = J 2 nd 1 st x R h
19 15 eldifad φ X V
20 1 2 3 4 5 6 7 8 9 10 11 12 13 14 19 16 17 hdmap1val φ I X F Y = if Y = 0 ˙ Q ι g D | M N Y = J g M N X - ˙ Y = J F R g
21 18 hdmap1cbv L = w V if 2 nd w = 0 ˙ Q ι g D | M N 2 nd w = J g M N 1 st 1 st w - ˙ 2 nd w = J 2 nd 1 st w R g
22 10 21 19 16 17 mapdhval φ L X F Y = if Y = 0 ˙ Q ι g D | M N Y = J g M N X - ˙ Y = J F R g
23 20 22 eqtr4d φ I X F Y = L X F Y