Metamath Proof Explorer


Theorem hvmul0

Description: Scalar multiplication with the zero vector. (Contributed by NM, 30-May-1999) (New usage is discouraged.)

Ref Expression
Assertion hvmul0 ⊢ A ∈ ℂ → A ⋅ ℎ 0 ℎ = 0 ℎ

Proof

Step Hyp Ref Expression
1 mul01 ⊢ A ∈ ℂ → A ⋅ 0 = 0
2 1 oveq1d ⊢ A ∈ ℂ → A ⋅ 0 ⋅ ℎ 0 ℎ = 0 ⋅ ℎ 0 ℎ
3 ax-hv0cl ⊢ 0 ℎ ∈ ℋ
4 ax-hvmul0 ⊢ 0 ℎ ∈ ℋ → 0 ⋅ ℎ 0 ℎ = 0 ℎ
5 3 4 ax-mp ⊢ 0 ⋅ ℎ 0 ℎ = 0 ℎ
6 2 5 eqtrdi ⊢ A ∈ ℂ → A ⋅ 0 ⋅ ℎ 0 ℎ = 0 ℎ
7 0cn ⊢ 0 ∈ ℂ
8 ax-hvmulass ⊢ A ∈ ℂ ∧ 0 ∈ ℂ ∧ 0 ℎ ∈ ℋ → A ⋅ 0 ⋅ ℎ 0 ℎ = A ⋅ ℎ 0 ⋅ ℎ 0 ℎ
9 7 3 8 mp3an23 ⊢ A ∈ ℂ → A ⋅ 0 ⋅ ℎ 0 ℎ = A ⋅ ℎ 0 ⋅ ℎ 0 ℎ
10 6 9 eqtr3d ⊢ A ∈ ℂ → 0 ℎ = A ⋅ ℎ 0 ⋅ ℎ 0 ℎ
11 5 oveq2i ⊢ A ⋅ ℎ 0 ⋅ ℎ 0 ℎ = A ⋅ ℎ 0 ℎ
12 10 11 eqtr2di ⊢ A ∈ ℂ → A ⋅ ℎ 0 ℎ = 0 ℎ