Metamath Proof Explorer


Theorem ifr0

Description: A class that is founded by the identity relation is null. (Contributed by Andrew Salmon, 25-Jul-2011)

Ref Expression
Assertion ifr0 ⊢ I Fr A ↔ A = ∅

Proof

Step Hyp Ref Expression
1 equid ⊢ x = x
2 vex ⊢ x ∈ V
3 2 ideq ⊢ x I x ↔ x = x
4 1 3 mpbir ⊢ x I x
5 frirr ⊢ I Fr A ∧ x ∈ A → ¬ x I x
6 5 ex ⊢ I Fr A → x ∈ A → ¬ x I x
7 4 6 mt2i ⊢ I Fr A → ¬ x ∈ A
8 7 eq0rdv ⊢ I Fr A → A = ∅
9 fr0 ⊢ I Fr ∅
10 freq2 ⊢ A = ∅ → I Fr A ↔ I Fr ∅
11 9 10 mpbiri ⊢ A = ∅ → I Fr A
12 8 11 impbii ⊢ I Fr A ↔ A = ∅