Metamath Proof Explorer


Theorem ige2m1fz

Description: Membership in a 0-based finite set of sequential integers. (Contributed by Alexander van der Vekens, 18-Jun-2018) (Proof shortened by Alexander van der Vekens, 15-Sep-2018)

Ref Expression
Assertion ige2m1fz ⊢ N ∈ ℕ 0 ∧ 2 ≤ N → N − 1 ∈ 0 … N

Proof

Step Hyp Ref Expression
1 1eluzge0 ⊢ 1 ∈ ℤ ≥ 0
2 fzss1 ⊢ 1 ∈ ℤ ≥ 0 → 1 … N ⊆ 0 … N
3 1 2 ax-mp ⊢ 1 … N ⊆ 0 … N
4 2z ⊢ 2 ∈ ℤ
5 4 a1i ⊢ N ∈ ℕ 0 ∧ 2 ≤ N → 2 ∈ ℤ
6 nn0z ⊢ N ∈ ℕ 0 → N ∈ ℤ
7 6 adantr ⊢ N ∈ ℕ 0 ∧ 2 ≤ N → N ∈ ℤ
8 simpr ⊢ N ∈ ℕ 0 ∧ 2 ≤ N → 2 ≤ N
9 eluz2 ⊢ N ∈ ℤ ≥ 2 ↔ 2 ∈ ℤ ∧ N ∈ ℤ ∧ 2 ≤ N
10 5 7 8 9 syl3anbrc ⊢ N ∈ ℕ 0 ∧ 2 ≤ N → N ∈ ℤ ≥ 2
11 ige2m1fz1 ⊢ N ∈ ℤ ≥ 2 → N − 1 ∈ 1 … N
12 10 11 syl ⊢ N ∈ ℕ 0 ∧ 2 ≤ N → N − 1 ∈ 1 … N
13 3 12 sselid ⊢ N ∈ ℕ 0 ∧ 2 ≤ N → N − 1 ∈ 0 … N