Metamath Proof Explorer


Theorem iineq2d

Description: Equality deduction for indexed intersection. (Contributed by NM, 7-Dec-2011)

Ref Expression
Hypotheses iineq2d.1 x φ
iineq2d.2 φ x A B = C
Assertion iineq2d φ x A B = x A C

Proof

Step Hyp Ref Expression
1 iineq2d.1 x φ
2 iineq2d.2 φ x A B = C
3 2 ex φ x A B = C
4 1 3 ralrimi φ x A B = C
5 iineq2 x A B = C x A B = x A C
6 4 5 syl φ x A B = x A C