Metamath Proof Explorer


Theorem iinfssclem2

Description: Lemma for iinfssc . (Contributed by Zhi Wang, 31-Oct-2025)

Ref Expression
Hypotheses iinfssc.1 ⊢ φ → A ≠ ∅
iinfssc.2 ⊢ φ ∧ x ∈ A → H ⊆ cat J
iinfssc.3 ⊢ φ → K = y ∈ ⋂ x ∈ A dom ⁡ H ⟼ ⋂ x ∈ A H ⁡ y
iinfssclem1.4 ⊢ φ ∧ x ∈ A → S = dom ⁡ dom ⁡ H
iinfssclem1.5 ⊢ Ⅎ x φ
Assertion iinfssclem2 ⊢ φ → K Fn ⋂ x ∈ A S × ⋂ x ∈ A S

Proof

Step Hyp Ref Expression
1 iinfssc.1 ⊢ φ → A ≠ ∅
2 iinfssc.2 ⊢ φ ∧ x ∈ A → H ⊆ cat J
3 iinfssc.3 ⊢ φ → K = y ∈ ⋂ x ∈ A dom ⁡ H ⟼ ⋂ x ∈ A H ⁡ y
4 iinfssclem1.4 ⊢ φ ∧ x ∈ A → S = dom ⁡ dom ⁡ H
5 iinfssclem1.5 ⊢ Ⅎ x φ
6 ovex ⊢ z H w ∈ V
7 6 rgenw ⊢ ∀ x ∈ A z H w ∈ V
8 iinexg ⊢ A ≠ ∅ ∧ ∀ x ∈ A z H w ∈ V → ⋂ x ∈ A z H w ∈ V
9 1 7 8 sylancl ⊢ φ → ⋂ x ∈ A z H w ∈ V
10 9 adantr ⊢ φ ∧ z ∈ ⋂ x ∈ A S ∧ w ∈ ⋂ x ∈ A S → ⋂ x ∈ A z H w ∈ V
11 10 ralrimivva ⊢ φ → ∀ z ∈ ⋂ x ∈ A S ∀ w ∈ ⋂ x ∈ A S ⋂ x ∈ A z H w ∈ V
12 eqid ⊢ z ∈ ⋂ x ∈ A S , w ∈ ⋂ x ∈ A S ⟼ ⋂ x ∈ A z H w = z ∈ ⋂ x ∈ A S , w ∈ ⋂ x ∈ A S ⟼ ⋂ x ∈ A z H w
13 12 fnmpo ⊢ ∀ z ∈ ⋂ x ∈ A S ∀ w ∈ ⋂ x ∈ A S ⋂ x ∈ A z H w ∈ V → z ∈ ⋂ x ∈ A S , w ∈ ⋂ x ∈ A S ⟼ ⋂ x ∈ A z H w Fn ⋂ x ∈ A S × ⋂ x ∈ A S
14 11 13 syl ⊢ φ → z ∈ ⋂ x ∈ A S , w ∈ ⋂ x ∈ A S ⟼ ⋂ x ∈ A z H w Fn ⋂ x ∈ A S × ⋂ x ∈ A S
15 1 2 3 4 5 iinfssclem1 ⊢ φ → K = z ∈ ⋂ x ∈ A S , w ∈ ⋂ x ∈ A S ⟼ ⋂ x ∈ A z H w
16 15 fneq1d ⊢ φ → K Fn ⋂ x ∈ A S × ⋂ x ∈ A S ↔ z ∈ ⋂ x ∈ A S , w ∈ ⋂ x ∈ A S ⟼ ⋂ x ∈ A z H w Fn ⋂ x ∈ A S × ⋂ x ∈ A S
17 14 16 mpbird ⊢ φ → K Fn ⋂ x ∈ A S × ⋂ x ∈ A S