Metamath Proof Explorer


Theorem imval2

Description: The imaginary part of a number in terms of complex conjugate. (Contributed by NM, 30-Apr-2005)

Ref Expression
Assertion imval2 ⊢ A ∈ ℂ → ℑ ⁡ A = A − A ‾ 2 ⁢ i

Proof

Step Hyp Ref Expression
1 imcl ⊢ A ∈ ℂ → ℑ ⁡ A ∈ ℝ
2 1 recnd ⊢ A ∈ ℂ → ℑ ⁡ A ∈ ℂ
3 2mulicn ⊢ 2 ⁢ i ∈ ℂ
4 2muline0 ⊢ 2 ⁢ i ≠ 0
5 divcan4 ⊢ ℑ ⁡ A ∈ ℂ ∧ 2 ⁢ i ∈ ℂ ∧ 2 ⁢ i ≠ 0 → ℑ ⁡ A ⁢ 2 ⁢ i 2 ⁢ i = ℑ ⁡ A
6 3 4 5 mp3an23 ⊢ ℑ ⁡ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i 2 ⁢ i = ℑ ⁡ A
7 2 6 syl ⊢ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i 2 ⁢ i = ℑ ⁡ A
8 recl ⊢ A ∈ ℂ → ℜ ⁡ A ∈ ℝ
9 8 recnd ⊢ A ∈ ℂ → ℜ ⁡ A ∈ ℂ
10 ax-icn ⊢ i ∈ ℂ
11 mulcl ⊢ i ∈ ℂ ∧ ℑ ⁡ A ∈ ℂ → i ⁢ ℑ ⁡ A ∈ ℂ
12 10 2 11 sylancr ⊢ A ∈ ℂ → i ⁢ ℑ ⁡ A ∈ ℂ
13 9 12 addcld ⊢ A ∈ ℂ → ℜ ⁡ A + i ⁢ ℑ ⁡ A ∈ ℂ
14 13 9 12 subsubd ⊢ A ∈ ℂ → ℜ ⁡ A + i ⁢ ℑ ⁡ A - ℜ ⁡ A − i ⁢ ℑ ⁡ A = ℜ ⁡ A + i ⁢ ℑ ⁡ A - ℜ ⁡ A + i ⁢ ℑ ⁡ A
15 replim ⊢ A ∈ ℂ → A = ℜ ⁡ A + i ⁢ ℑ ⁡ A
16 remim ⊢ A ∈ ℂ → A ‾ = ℜ ⁡ A − i ⁢ ℑ ⁡ A
17 15 16 oveq12d ⊢ A ∈ ℂ → A − A ‾ = ℜ ⁡ A + i ⁢ ℑ ⁡ A - ℜ ⁡ A − i ⁢ ℑ ⁡ A
18 12 2timesd ⊢ A ∈ ℂ → 2 ⁢ i ⁢ ℑ ⁡ A = i ⁢ ℑ ⁡ A + i ⁢ ℑ ⁡ A
19 mulcom ⊢ ℑ ⁡ A ∈ ℂ ∧ 2 ⁢ i ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i = 2 ⁢ i ⁢ ℑ ⁡ A
20 3 19 mpan2 ⊢ ℑ ⁡ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i = 2 ⁢ i ⁢ ℑ ⁡ A
21 2cn ⊢ 2 ∈ ℂ
22 mulass ⊢ 2 ∈ ℂ ∧ i ∈ ℂ ∧ ℑ ⁡ A ∈ ℂ → 2 ⁢ i ⁢ ℑ ⁡ A = 2 ⁢ i ⁢ ℑ ⁡ A
23 21 10 22 mp3an12 ⊢ ℑ ⁡ A ∈ ℂ → 2 ⁢ i ⁢ ℑ ⁡ A = 2 ⁢ i ⁢ ℑ ⁡ A
24 20 23 eqtrd ⊢ ℑ ⁡ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i = 2 ⁢ i ⁢ ℑ ⁡ A
25 2 24 syl ⊢ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i = 2 ⁢ i ⁢ ℑ ⁡ A
26 9 12 pncan2d ⊢ A ∈ ℂ → ℜ ⁡ A + i ⁢ ℑ ⁡ A - ℜ ⁡ A = i ⁢ ℑ ⁡ A
27 26 oveq1d ⊢ A ∈ ℂ → ℜ ⁡ A + i ⁢ ℑ ⁡ A - ℜ ⁡ A + i ⁢ ℑ ⁡ A = i ⁢ ℑ ⁡ A + i ⁢ ℑ ⁡ A
28 18 25 27 3eqtr4d ⊢ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i = ℜ ⁡ A + i ⁢ ℑ ⁡ A - ℜ ⁡ A + i ⁢ ℑ ⁡ A
29 14 17 28 3eqtr4rd ⊢ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i = A − A ‾
30 29 oveq1d ⊢ A ∈ ℂ → ℑ ⁡ A ⁢ 2 ⁢ i 2 ⁢ i = A − A ‾ 2 ⁢ i
31 7 30 eqtr3d ⊢ A ∈ ℂ → ℑ ⁡ A = A − A ‾ 2 ⁢ i