Metamath Proof Explorer


Theorem indisconn

Description: The indiscrete topology (or trivial topology) on any set is connected. (Contributed by FL, 5-Jan-2009) (Revised by Mario Carneiro, 14-Aug-2015)

Ref Expression
Assertion indisconn ⊢ ∅ A ∈ Conn

Proof

Step Hyp Ref Expression
1 indistop ⊢ ∅ A ∈ Top
2 inss1 ⊢ ∅ A ∩ Clsd ⁡ ∅ A ⊆ ∅ A
3 indislem ⊢ ∅ I ⁡ A = ∅ A
4 2 3 sseqtrri ⊢ ∅ A ∩ Clsd ⁡ ∅ A ⊆ ∅ I ⁡ A
5 indisuni ⊢ I ⁡ A = ⋃ ∅ A
6 5 isconn2 ⊢ ∅ A ∈ Conn ↔ ∅ A ∈ Top ∧ ∅ A ∩ Clsd ⁡ ∅ A ⊆ ∅ I ⁡ A
7 1 4 6 mpbir2an ⊢ ∅ A ∈ Conn