Metamath Proof Explorer


Theorem irrednzr

Description: A ring with an irreducible element cannot be the zero ring. (Contributed by Thierry Arnoux, 18-May-2025)

Ref Expression
Hypotheses irrednzr.1 ⊢ I = Irred ⁡ R
irrednzr.2 ⊢ φ → R ∈ Ring
irrednzr.3 ⊢ φ → X ∈ I
Assertion irrednzr ⊢ φ → R ∈ NzRing

Proof

Step Hyp Ref Expression
1 irrednzr.1 ⊢ I = Irred ⁡ R
2 irrednzr.2 ⊢ φ → R ∈ Ring
3 irrednzr.3 ⊢ φ → X ∈ I
4 eqid ⊢ Base R = Base R
5 1 4 irredcl ⊢ X ∈ I → X ∈ Base R
6 3 5 syl ⊢ φ → X ∈ Base R
7 eqid ⊢ 0 R = 0 R
8 1 7 irredn0 ⊢ R ∈ Ring ∧ X ∈ I → X ≠ 0 R
9 2 3 8 syl2anc ⊢ φ → X ≠ 0 R
10 6 9 eldifsnd ⊢ φ → X ∈ Base R ∖ 0 R
11 7 4 ringelnzr ⊢ R ∈ Ring ∧ X ∈ Base R ∖ 0 R → R ∈ NzRing
12 2 10 11 syl2anc ⊢ φ → R ∈ NzRing