Metamath Proof Explorer


Theorem isfieldidl2

Description: Determine if a ring is a field based on its ideals. (Contributed by Jeff Madsen, 6-Jan-2011) (Revised by AV, 30-Jun-2026)

Ref Expression
Hypotheses isfieldidl.b ⊢ B = Base R
isfieldidl.0 ⊢ 0 ˙ = 0 R
isfieldidl.i ⊢ I = LIdeal ⁡ R
Assertion isfieldidl2 ⊢ R ∈ Field ↔ R ∈ CRing ∧ B ≠ 0 ˙ ∧ I = 0 ˙ B

Proof

Step Hyp Ref Expression
1 isfieldidl.b ⊢ B = Base R
2 isfieldidl.0 ⊢ 0 ˙ = 0 R
3 isfieldidl.i ⊢ I = LIdeal ⁡ R
4 eqid ⊢ 1 R = 1 R
5 1 2 3 4 isfieldidl ⊢ R ∈ Field ↔ R ∈ CRing ∧ 0 ˙ ≠ 1 R ∧ I = 0 ˙ B
6 crngring ⊢ R ∈ CRing → R ∈ Ring
7 eqcom ⊢ 0 ˙ = 1 R ↔ 1 R = 0 ˙
8 1 2 4 0ring01eqbi2 ⊢ R ∈ Ring → B = 0 ˙ ↔ 1 R = 0 ˙
9 7 8 bitr4id ⊢ R ∈ Ring → 0 ˙ = 1 R ↔ B = 0 ˙
10 6 9 syl ⊢ R ∈ CRing → 0 ˙ = 1 R ↔ B = 0 ˙
11 10 necon3bid ⊢ R ∈ CRing → 0 ˙ ≠ 1 R ↔ B ≠ 0 ˙
12 11 anbi1d ⊢ R ∈ CRing → 0 ˙ ≠ 1 R ∧ I = 0 ˙ B ↔ B ≠ 0 ˙ ∧ I = 0 ˙ B
13 12 pm5.32i ⊢ R ∈ CRing ∧ 0 ˙ ≠ 1 R ∧ I = 0 ˙ B ↔ R ∈ CRing ∧ B ≠ 0 ˙ ∧ I = 0 ˙ B
14 3anass ⊢ R ∈ CRing ∧ 0 ˙ ≠ 1 R ∧ I = 0 ˙ B ↔ R ∈ CRing ∧ 0 ˙ ≠ 1 R ∧ I = 0 ˙ B
15 3anass ⊢ R ∈ CRing ∧ B ≠ 0 ˙ ∧ I = 0 ˙ B ↔ R ∈ CRing ∧ B ≠ 0 ˙ ∧ I = 0 ˙ B
16 13 14 15 3bitr4i ⊢ R ∈ CRing ∧ 0 ˙ ≠ 1 R ∧ I = 0 ˙ B ↔ R ∈ CRing ∧ B ≠ 0 ˙ ∧ I = 0 ˙ B
17 5 16 bitri ⊢ R ∈ Field ↔ R ∈ CRing ∧ B ≠ 0 ˙ ∧ I = 0 ˙ B