Metamath Proof Explorer


Theorem isrnghm2d

Description: Demonstration of non-unital ring homomorphism. (Contributed by AV, 23-Feb-2020)

Ref Expression
Hypotheses isrnghmd.b ⊢ B = Base R
isrnghmd.t ⊢ · ˙ = ⋅ R
isrnghmd.u ⊢ × ˙ = ⋅ S
isrnghmd.r ⊢ φ → R ∈ Rng
isrnghmd.s ⊢ φ → S ∈ Rng
isrnghmd.ht ⊢ φ ∧ x ∈ B ∧ y ∈ B → F ⁡ x · ˙ y = F ⁡ x × ˙ F ⁡ y
isrnghm2d.f ⊢ φ → F ∈ R GrpHom S
Assertion isrnghm2d ⊢ φ → F ∈ R RngHom S

Proof

Step Hyp Ref Expression
1 isrnghmd.b ⊢ B = Base R
2 isrnghmd.t ⊢ · ˙ = ⋅ R
3 isrnghmd.u ⊢ × ˙ = ⋅ S
4 isrnghmd.r ⊢ φ → R ∈ Rng
5 isrnghmd.s ⊢ φ → S ∈ Rng
6 isrnghmd.ht ⊢ φ ∧ x ∈ B ∧ y ∈ B → F ⁡ x · ˙ y = F ⁡ x × ˙ F ⁡ y
7 isrnghm2d.f ⊢ φ → F ∈ R GrpHom S
8 4 5 jca ⊢ φ → R ∈ Rng ∧ S ∈ Rng
9 6 ralrimivva ⊢ φ → ∀ x ∈ B ∀ y ∈ B F ⁡ x · ˙ y = F ⁡ x × ˙ F ⁡ y
10 7 9 jca ⊢ φ → F ∈ R GrpHom S ∧ ∀ x ∈ B ∀ y ∈ B F ⁡ x · ˙ y = F ⁡ x × ˙ F ⁡ y
11 1 2 3 isrnghm ⊢ F ∈ R RngHom S ↔ R ∈ Rng ∧ S ∈ Rng ∧ F ∈ R GrpHom S ∧ ∀ x ∈ B ∀ y ∈ B F ⁡ x · ˙ y = F ⁡ x × ˙ F ⁡ y
12 8 10 11 sylanbrc ⊢ φ → F ∈ R RngHom S