Metamath Proof Explorer


Theorem itgre

Description: Real part of an integral. (Contributed by Mario Carneiro, 14-Aug-2014)

Ref Expression
Hypotheses itgcnval.1 ⊢ φ ∧ x ∈ A → B ∈ V
itgcnval.2 ⊢ φ → x ∈ A ⟼ B ∈ 𝐿 1
Assertion itgre ⊢ φ → ℜ ⁡ ∫ A B dx = ∫ A ℜ ⁡ B dx

Proof

Step Hyp Ref Expression
1 itgcnval.1 ⊢ φ ∧ x ∈ A → B ∈ V
2 itgcnval.2 ⊢ φ → x ∈ A ⟼ B ∈ 𝐿 1
3 1 2 itgcnval ⊢ φ → ∫ A B dx = ∫ A ℜ ⁡ B dx + i ⁢ ∫ A ℑ ⁡ B dx
4 3 fveq2d ⊢ φ → ℜ ⁡ ∫ A B dx = ℜ ⁡ ∫ A ℜ ⁡ B dx + i ⁢ ∫ A ℑ ⁡ B dx
5 iblmbf ⊢ x ∈ A ⟼ B ∈ 𝐿 1 → x ∈ A ⟼ B ∈ MblFn
6 2 5 syl ⊢ φ → x ∈ A ⟼ B ∈ MblFn
7 6 1 mbfmptcl ⊢ φ ∧ x ∈ A → B ∈ ℂ
8 7 recld ⊢ φ ∧ x ∈ A → ℜ ⁡ B ∈ ℝ
9 7 iblcn ⊢ φ → x ∈ A ⟼ B ∈ 𝐿 1 ↔ x ∈ A ⟼ ℜ ⁡ B ∈ 𝐿 1 ∧ x ∈ A ⟼ ℑ ⁡ B ∈ 𝐿 1
10 2 9 mpbid ⊢ φ → x ∈ A ⟼ ℜ ⁡ B ∈ 𝐿 1 ∧ x ∈ A ⟼ ℑ ⁡ B ∈ 𝐿 1
11 10 simpld ⊢ φ → x ∈ A ⟼ ℜ ⁡ B ∈ 𝐿 1
12 8 11 itgrecl ⊢ φ → ∫ A ℜ ⁡ B dx ∈ ℝ
13 7 imcld ⊢ φ ∧ x ∈ A → ℑ ⁡ B ∈ ℝ
14 10 simprd ⊢ φ → x ∈ A ⟼ ℑ ⁡ B ∈ 𝐿 1
15 13 14 itgrecl ⊢ φ → ∫ A ℑ ⁡ B dx ∈ ℝ
16 12 15 crred ⊢ φ → ℜ ⁡ ∫ A ℜ ⁡ B dx + i ⁢ ∫ A ℑ ⁡ B dx = ∫ A ℜ ⁡ B dx
17 4 16 eqtrd ⊢ φ → ℜ ⁡ ∫ A B dx = ∫ A ℜ ⁡ B dx