Metamath Proof Explorer
Description: Every vector space has a basis. This theorem is an AC equivalent.
(Contributed by Mario Carneiro, 25-Jun-2014)
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|
Ref |
Expression |
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Hypothesis |
lbsex.j |
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Assertion |
lbsex |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
lbsex.j |
|
2 |
|
axac3 |
|
3 |
1
|
lbsexg |
|
4 |
2 3
|
mpan |
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