Metamath Proof Explorer
		
		
		
		Description:  Every vector space has a basis.  This theorem is an AC equivalent.
       (Contributed by Mario Carneiro, 25-Jun-2014)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | lbsex.j |  | 
				
					|  | Assertion | lbsex |  | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | lbsex.j |  | 
						
							| 2 |  | axac3 |  | 
						
							| 3 | 1 | lbsexg |  | 
						
							| 4 | 2 3 | mpan |  |