Metamath Proof Explorer


Theorem lcfrlem13

Description: Lemma for lcfr . (Contributed by NM, 8-Mar-2015)

Ref Expression
Hypotheses lcf1o.h ⊢ H = LHyp ⁡ K
lcf1o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
lcf1o.u ⊢ U = DVecH ⁡ K ⁡ W
lcf1o.v ⊢ V = Base U
lcf1o.a ⊢ + ˙ = + U
lcf1o.t ⊢ · ˙ = ⋅ U
lcf1o.s ⊢ S = Scalar ⁡ U
lcf1o.r ⊢ R = Base S
lcf1o.z ⊢ 0 ˙ = 0 U
lcf1o.f ⊢ F = LFnl ⁡ U
lcf1o.l ⊢ L = LKer ⁡ U
lcf1o.d ⊢ D = LDual ⁡ U
lcf1o.q ⊢ Q = 0 D
lcf1o.c ⊢ C = f ∈ F | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f
lcf1o.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
lcflo.k ⊢ φ → K ∈ HL ∧ W ∈ H
lcfrlem10.x ⊢ φ → X ∈ V ∖ 0 ˙
Assertion lcfrlem13 ⊢ φ → J ⁡ X ∈ C ∖ Q

Proof

Step Hyp Ref Expression
1 lcf1o.h ⊢ H = LHyp ⁡ K
2 lcf1o.o ⊢ ⊥ ˙ = ocH ⁡ K ⁡ W
3 lcf1o.u ⊢ U = DVecH ⁡ K ⁡ W
4 lcf1o.v ⊢ V = Base U
5 lcf1o.a ⊢ + ˙ = + U
6 lcf1o.t ⊢ · ˙ = ⋅ U
7 lcf1o.s ⊢ S = Scalar ⁡ U
8 lcf1o.r ⊢ R = Base S
9 lcf1o.z ⊢ 0 ˙ = 0 U
10 lcf1o.f ⊢ F = LFnl ⁡ U
11 lcf1o.l ⊢ L = LKer ⁡ U
12 lcf1o.d ⊢ D = LDual ⁡ U
13 lcf1o.q ⊢ Q = 0 D
14 lcf1o.c ⊢ C = f ∈ F | ⊥ ˙ ⁡ ⊥ ˙ ⁡ L ⁡ f = L ⁡ f
15 lcf1o.j ⊢ J = x ∈ V ∖ 0 ˙ ⟼ v ∈ V ⟼ ι k ∈ R | ∃ w ∈ ⊥ ˙ ⁡ x v = w + ˙ k · ˙ x
16 lcflo.k ⊢ φ → K ∈ HL ∧ W ∈ H
17 lcfrlem10.x ⊢ φ → X ∈ V ∖ 0 ˙
18 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 lcf1o ⊢ φ → J : V ∖ 0 ˙ ⟶ 1-1 onto C ∖ Q
19 f1of ⊢ J : V ∖ 0 ˙ ⟶ 1-1 onto C ∖ Q → J : V ∖ 0 ˙ ⟶ C ∖ Q
20 18 19 syl ⊢ φ → J : V ∖ 0 ˙ ⟶ C ∖ Q
21 20 17 ffvelcdmd ⊢ φ → J ⁡ X ∈ C ∖ Q