Metamath Proof Explorer


Theorem ldual0vcl

Description: The dual zero vector is a functional. (Contributed by NM, 5-Mar-2015)

Ref Expression
Hypotheses ldualv0cl.f ⊢ F = LFnl ⁡ W
ldualv0cl.d ⊢ D = LDual ⁡ W
ldualv0cl.o ⊢ 0 ˙ = 0 D
ldualv0cl.w ⊢ φ → W ∈ LMod
Assertion ldual0vcl ⊢ φ → 0 ˙ ∈ F

Proof

Step Hyp Ref Expression
1 ldualv0cl.f ⊢ F = LFnl ⁡ W
2 ldualv0cl.d ⊢ D = LDual ⁡ W
3 ldualv0cl.o ⊢ 0 ˙ = 0 D
4 ldualv0cl.w ⊢ φ → W ∈ LMod
5 eqid ⊢ Base W = Base W
6 eqid ⊢ Scalar ⁡ W = Scalar ⁡ W
7 eqid ⊢ 0 Scalar ⁡ W = 0 Scalar ⁡ W
8 5 6 7 2 3 4 ldual0v ⊢ φ → 0 ˙ = Base W × 0 Scalar ⁡ W
9 6 7 5 1 lfl0f ⊢ W ∈ LMod → Base W × 0 Scalar ⁡ W ∈ F
10 4 9 syl ⊢ φ → Base W × 0 Scalar ⁡ W ∈ F
11 8 10 eqeltrd ⊢ φ → 0 ˙ ∈ F