Metamath Proof Explorer


Theorem lindslinindimp2lem1

Description: Lemma 1 for lindslinindsimp2 . (Contributed by AV, 25-Apr-2019)

Ref Expression
Hypotheses lindslinind.r ⊢ R = Scalar ⁡ M
lindslinind.b ⊢ B = Base R
lindslinind.0 ⊢ 0 ˙ = 0 R
lindslinind.z ⊢ Z = 0 M
lindslinind.y ⊢ Y = inv g ⁡ R ⁡ f ⁡ x
lindslinind.g ⊢ G = f ↾ S ∖ x
Assertion lindslinindimp2lem1 ⊢ S ∈ V ∧ M ∈ LMod ∧ S ⊆ Base M ∧ x ∈ S ∧ f ∈ B S → Y ∈ B

Proof

Step Hyp Ref Expression
1 lindslinind.r ⊢ R = Scalar ⁡ M
2 lindslinind.b ⊢ B = Base R
3 lindslinind.0 ⊢ 0 ˙ = 0 R
4 lindslinind.z ⊢ Z = 0 M
5 lindslinind.y ⊢ Y = inv g ⁡ R ⁡ f ⁡ x
6 lindslinind.g ⊢ G = f ↾ S ∖ x
7 1 lmodfgrp ⊢ M ∈ LMod → R ∈ Grp
8 7 adantl ⊢ S ∈ V ∧ M ∈ LMod → R ∈ Grp
9 elmapi ⊢ f ∈ B S → f : S ⟶ B
10 ffvelcdm ⊢ f : S ⟶ B ∧ x ∈ S → f ⁡ x ∈ B
11 10 a1d ⊢ f : S ⟶ B ∧ x ∈ S → S ⊆ Base M → f ⁡ x ∈ B
12 11 ex ⊢ f : S ⟶ B → x ∈ S → S ⊆ Base M → f ⁡ x ∈ B
13 9 12 syl ⊢ f ∈ B S → x ∈ S → S ⊆ Base M → f ⁡ x ∈ B
14 13 com13 ⊢ S ⊆ Base M → x ∈ S → f ∈ B S → f ⁡ x ∈ B
15 14 3imp ⊢ S ⊆ Base M ∧ x ∈ S ∧ f ∈ B S → f ⁡ x ∈ B
16 eqid ⊢ inv g ⁡ R = inv g ⁡ R
17 2 16 grpinvcl ⊢ R ∈ Grp ∧ f ⁡ x ∈ B → inv g ⁡ R ⁡ f ⁡ x ∈ B
18 8 15 17 syl2an ⊢ S ∈ V ∧ M ∈ LMod ∧ S ⊆ Base M ∧ x ∈ S ∧ f ∈ B S → inv g ⁡ R ⁡ f ⁡ x ∈ B
19 5 18 eqeltrid ⊢ S ∈ V ∧ M ∈ LMod ∧ S ⊆ Base M ∧ x ∈ S ∧ f ∈ B S → Y ∈ B