Metamath Proof Explorer


Theorem lmodvsubcl

Description: Closure of vector subtraction. ( hvsubcl analog.) (Contributed by NM, 31-Mar-2014) (Revised by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypotheses lmodvsubcl.v ⊢ V = Base W
lmodvsubcl.m ⊢ - ˙ = - W
Assertion lmodvsubcl ⊢ W ∈ LMod ∧ X ∈ V ∧ Y ∈ V → X - ˙ Y ∈ V

Proof

Step Hyp Ref Expression
1 lmodvsubcl.v ⊢ V = Base W
2 lmodvsubcl.m ⊢ - ˙ = - W
3 lmodgrp ⊢ W ∈ LMod → W ∈ Grp
4 1 2 grpsubcl ⊢ W ∈ Grp ∧ X ∈ V ∧ Y ∈ V → X - ˙ Y ∈ V
5 3 4 syl3an1 ⊢ W ∈ LMod ∧ X ∈ V ∧ Y ∈ V → X - ˙ Y ∈ V