Metamath Proof Explorer


Theorem lspsneq0

Description: Span of the singleton is the zero subspace iff the vector is zero. (Contributed by NM, 27-Apr-2014) (Revised by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypotheses lspsneq0.v ⊢ V = Base W
lspsneq0.z ⊢ 0 ˙ = 0 W
lspsneq0.n ⊢ N = LSpan ⁡ W
Assertion lspsneq0 ⊢ W ∈ LMod ∧ X ∈ V → N ⁡ X = 0 ˙ ↔ X = 0 ˙

Proof

Step Hyp Ref Expression
1 lspsneq0.v ⊢ V = Base W
2 lspsneq0.z ⊢ 0 ˙ = 0 W
3 lspsneq0.n ⊢ N = LSpan ⁡ W
4 1 3 lspsnid ⊢ W ∈ LMod ∧ X ∈ V → X ∈ N ⁡ X
5 eleq2 ⊢ N ⁡ X = 0 ˙ → X ∈ N ⁡ X ↔ X ∈ 0 ˙
6 4 5 syl5ibcom ⊢ W ∈ LMod ∧ X ∈ V → N ⁡ X = 0 ˙ → X ∈ 0 ˙
7 elsni ⊢ X ∈ 0 ˙ → X = 0 ˙
8 6 7 syl6 ⊢ W ∈ LMod ∧ X ∈ V → N ⁡ X = 0 ˙ → X = 0 ˙
9 2 3 lspsn0 ⊢ W ∈ LMod → N ⁡ 0 ˙ = 0 ˙
10 9 adantr ⊢ W ∈ LMod ∧ X ∈ V → N ⁡ 0 ˙ = 0 ˙
11 sneq ⊢ X = 0 ˙ → X = 0 ˙
12 11 fveqeq2d ⊢ X = 0 ˙ → N ⁡ X = 0 ˙ ↔ N ⁡ 0 ˙ = 0 ˙
13 10 12 syl5ibrcom ⊢ W ∈ LMod ∧ X ∈ V → X = 0 ˙ → N ⁡ X = 0 ˙
14 8 13 impbid ⊢ W ∈ LMod ∧ X ∈ V → N ⁡ X = 0 ˙ ↔ X = 0 ˙