Metamath Proof Explorer


Theorem lsssssubg

Description: All subspaces are subgroups. (Contributed by Mario Carneiro, 19-Apr-2016)

Ref Expression
Hypothesis lsssubg.s ⊢ S = LSubSp ⁡ W
Assertion lsssssubg ⊢ W ∈ LMod → S ⊆ SubGrp ⁡ W

Proof

Step Hyp Ref Expression
1 lsssubg.s ⊢ S = LSubSp ⁡ W
2 1 lsssubg ⊢ W ∈ LMod ∧ x ∈ S → x ∈ SubGrp ⁡ W
3 2 ex ⊢ W ∈ LMod → x ∈ S → x ∈ SubGrp ⁡ W
4 3 ssrdv ⊢ W ∈ LMod → S ⊆ SubGrp ⁡ W