Metamath Proof Explorer


Theorem metcld

Description: A subset of a metric space is closed iff every convergent sequence on it converges to a point in the subset. Theorem 1.4-6(b) of Kreyszig p. 30. (Contributed by NM, 11-Nov-2007) (Revised by Mario Carneiro, 1-May-2014)

Ref Expression
Hypothesis metcld.2 J=MetOpenD
Assertion metcld D∞MetXSXSClsdJxff:SftJxxS

Proof

Step Hyp Ref Expression
1 metcld.2 J=MetOpenD
2 1 mopntop D∞MetXJTop
3 1 mopnuni D∞MetXX=J
4 3 sseq2d D∞MetXSXSJ
5 4 biimpa D∞MetXSXSJ
6 eqid J=J
7 6 iscld4 JTopSJSClsdJclsJSS
8 2 5 7 syl2an2r D∞MetXSXSClsdJclsJSS
9 19.23v ff:SftJxxSff:SftJxxS
10 simpl D∞MetXSXD∞MetX
11 simpr D∞MetXSXSX
12 1 10 11 metelcls D∞MetXSXxclsJSff:SftJx
13 12 imbi1d D∞MetXSXxclsJSxSff:SftJxxS
14 9 13 bitr4id D∞MetXSXff:SftJxxSxclsJSxS
15 14 albidv D∞MetXSXxff:SftJxxSxxclsJSxS
16 dfss2 clsJSSxxclsJSxS
17 15 16 bitr4di D∞MetXSXxff:SftJxxSclsJSS
18 8 17 bitr4d D∞MetXSXSClsdJxff:SftJxxS