Metamath Proof Explorer


Theorem metelcls

Description: A point belongs to the closure of a subset iff there is a sequence in the subset converging to it. Theorem 1.4-6(a) of Kreyszig p. 30. This proof uses countable choice ax-cc . The statement can be generalized to first-countable spaces, not just metrizable spaces. (Contributed by NM, 8-Nov-2007) (Proof shortened by Mario Carneiro, 1-May-2015)

Ref Expression
Hypotheses metelcls.2 J=MetOpenD
metelcls.3 φD∞MetX
metelcls.5 φSX
Assertion metelcls φPclsJSff:SftJP

Proof

Step Hyp Ref Expression
1 metelcls.2 J=MetOpenD
2 metelcls.3 φD∞MetX
3 metelcls.5 φSX
4 1 met1stc D∞MetXJ1st𝜔
5 2 4 syl φJ1st𝜔
6 1 mopnuni D∞MetXX=J
7 2 6 syl φX=J
8 3 7 sseqtrd φSJ
9 eqid J=J
10 9 1stcelcls J1st𝜔SJPclsJSff:SftJP
11 5 8 10 syl2anc φPclsJSff:SftJP