Metamath Proof Explorer


Theorem metss2

Description: If the metric D is "strongly finer" than C (meaning that there is a positive real constant R such that C ( x , y ) <_ R x. D ( x , y ) ), then D generates a finer topology. (Using this theorem twice in each direction states that if two metrics are strongly equivalent, then they generate the same topology.) (Contributed by Mario Carneiro, 14-Sep-2015)

Ref Expression
Hypotheses metequiv.3 ⊢ J = MetOpen ⁡ C
metequiv.4 ⊢ K = MetOpen ⁡ D
metss2.1 ⊢ φ → C ∈ Met ⁡ X
metss2.2 ⊢ φ → D ∈ Met ⁡ X
metss2.3 ⊢ φ → R ∈ ℝ +
metss2.4 ⊢ φ ∧ x ∈ X ∧ y ∈ X → x C y ≤ R ⁢ x D y
Assertion metss2 ⊢ φ → J ⊆ K

Proof

Step Hyp Ref Expression
1 metequiv.3 ⊢ J = MetOpen ⁡ C
2 metequiv.4 ⊢ K = MetOpen ⁡ D
3 metss2.1 ⊢ φ → C ∈ Met ⁡ X
4 metss2.2 ⊢ φ → D ∈ Met ⁡ X
5 metss2.3 ⊢ φ → R ∈ ℝ +
6 metss2.4 ⊢ φ ∧ x ∈ X ∧ y ∈ X → x C y ≤ R ⁢ x D y
7 simpr ⊢ x ∈ X ∧ r ∈ ℝ + → r ∈ ℝ +
8 rpdivcl ⊢ r ∈ ℝ + ∧ R ∈ ℝ + → r R ∈ ℝ +
9 7 5 8 syl2anr ⊢ φ ∧ x ∈ X ∧ r ∈ ℝ + → r R ∈ ℝ +
10 1 2 3 4 5 6 metss2lem ⊢ φ ∧ x ∈ X ∧ r ∈ ℝ + → x ball ⁡ D r R ⊆ x ball ⁡ C r
11 oveq2 ⊢ s = r R → x ball ⁡ D s = x ball ⁡ D r R
12 11 sseq1d ⊢ s = r R → x ball ⁡ D s ⊆ x ball ⁡ C r ↔ x ball ⁡ D r R ⊆ x ball ⁡ C r
13 12 rspcev ⊢ r R ∈ ℝ + ∧ x ball ⁡ D r R ⊆ x ball ⁡ C r → ∃ s ∈ ℝ + x ball ⁡ D s ⊆ x ball ⁡ C r
14 9 10 13 syl2anc ⊢ φ ∧ x ∈ X ∧ r ∈ ℝ + → ∃ s ∈ ℝ + x ball ⁡ D s ⊆ x ball ⁡ C r
15 14 ralrimivva ⊢ φ → ∀ x ∈ X ∀ r ∈ ℝ + ∃ s ∈ ℝ + x ball ⁡ D s ⊆ x ball ⁡ C r
16 metxmet ⊢ C ∈ Met ⁡ X → C ∈ ∞Met ⁡ X
17 3 16 syl ⊢ φ → C ∈ ∞Met ⁡ X
18 metxmet ⊢ D ∈ Met ⁡ X → D ∈ ∞Met ⁡ X
19 4 18 syl ⊢ φ → D ∈ ∞Met ⁡ X
20 1 2 metss ⊢ C ∈ ∞Met ⁡ X ∧ D ∈ ∞Met ⁡ X → J ⊆ K ↔ ∀ x ∈ X ∀ r ∈ ℝ + ∃ s ∈ ℝ + x ball ⁡ D s ⊆ x ball ⁡ C r
21 17 19 20 syl2anc ⊢ φ → J ⊆ K ↔ ∀ x ∈ X ∀ r ∈ ℝ + ∃ s ∈ ℝ + x ball ⁡ D s ⊆ x ball ⁡ C r
22 15 21 mpbird ⊢ φ → J ⊆ K