Metamath Proof Explorer


Theorem midcgr

Description: Congruence of midpoint. (Contributed by Thierry Arnoux, 7-Dec-2019)

Ref Expression
Hypotheses ismid.p ⊢ P = Base G
ismid.d ⊢ - ˙ = dist ⁡ G
ismid.i ⊢ I = Itv ⁡ G
ismid.g ⊢ φ → G ∈ 𝒢 Tarski
ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
midcl.1 ⊢ φ → A ∈ P
midcl.2 ⊢ φ → B ∈ P
midcgr.1 ⊢ φ → A mid 𝒢 ⁡ G B = C
Assertion midcgr ⊢ φ → C - ˙ A = C - ˙ B

Proof

Step Hyp Ref Expression
1 ismid.p ⊢ P = Base G
2 ismid.d ⊢ - ˙ = dist ⁡ G
3 ismid.i ⊢ I = Itv ⁡ G
4 ismid.g ⊢ φ → G ∈ 𝒢 Tarski
5 ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
6 midcl.1 ⊢ φ → A ∈ P
7 midcl.2 ⊢ φ → B ∈ P
8 midcgr.1 ⊢ φ → A mid 𝒢 ⁡ G B = C
9 eqid ⊢ pInv 𝒢 ⁡ G = pInv 𝒢 ⁡ G
10 1 2 3 4 5 6 7 midcl ⊢ φ → A mid 𝒢 ⁡ G B ∈ P
11 8 10 eqeltrrd ⊢ φ → C ∈ P
12 1 2 3 4 5 6 7 9 11 ismidb ⊢ φ → B = pInv 𝒢 ⁡ G ⁡ C ⁡ A ↔ A mid 𝒢 ⁡ G B = C
13 8 12 mpbird ⊢ φ → B = pInv 𝒢 ⁡ G ⁡ C ⁡ A
14 13 oveq2d ⊢ φ → C - ˙ B = C - ˙ pInv 𝒢 ⁡ G ⁡ C ⁡ A
15 eqid ⊢ Line 𝒢 ⁡ G = Line 𝒢 ⁡ G
16 eqid ⊢ pInv 𝒢 ⁡ G ⁡ C = pInv 𝒢 ⁡ G ⁡ C
17 1 2 3 15 9 4 11 16 6 mircgr ⊢ φ → C - ˙ pInv 𝒢 ⁡ G ⁡ C ⁡ A = C - ˙ A
18 14 17 eqtr2d ⊢ φ → C - ˙ A = C - ˙ B