Metamath Proof Explorer


Theorem ndmaovass

Description: Any operation is associative outside its domain. In contrast to ndmovass where it is required that the operation's domain doesn't contain the empty set ( -. (/) e. S ), no additional assumption is required. (Contributed by Alexander van der Vekens, 26-May-2017)

Ref Expression
Hypothesis ndmaov.1 ⊢ dom ⁡ F = S × S
Assertion ndmaovass ⊢ ¬ A ∈ S ∧ B ∈ S ∧ C ∈ S → A F B F C = A F B F C

Proof

Step Hyp Ref Expression
1 ndmaov.1 ⊢ dom ⁡ F = S × S
2 1 eleq2i ⊢ A F B C ∈ dom ⁡ F ↔ A F B C ∈ S × S
3 opelxp ⊢ A F B C ∈ S × S ↔ A F B ∈ S ∧ C ∈ S
4 2 3 bitri ⊢ A F B C ∈ dom ⁡ F ↔ A F B ∈ S ∧ C ∈ S
5 aovvdm ⊢ A F B ∈ S → A B ∈ dom ⁡ F
6 1 eleq2i ⊢ A B ∈ dom ⁡ F ↔ A B ∈ S × S
7 opelxp ⊢ A B ∈ S × S ↔ A ∈ S ∧ B ∈ S
8 6 7 bitri ⊢ A B ∈ dom ⁡ F ↔ A ∈ S ∧ B ∈ S
9 df-3an ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ↔ A ∈ S ∧ B ∈ S ∧ C ∈ S
10 9 simplbi2 ⊢ A ∈ S ∧ B ∈ S → C ∈ S → A ∈ S ∧ B ∈ S ∧ C ∈ S
11 8 10 sylbi ⊢ A B ∈ dom ⁡ F → C ∈ S → A ∈ S ∧ B ∈ S ∧ C ∈ S
12 5 11 syl ⊢ A F B ∈ S → C ∈ S → A ∈ S ∧ B ∈ S ∧ C ∈ S
13 12 imp ⊢ A F B ∈ S ∧ C ∈ S → A ∈ S ∧ B ∈ S ∧ C ∈ S
14 4 13 sylbi ⊢ A F B C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
15 ndmaov ⊢ ¬ A F B C ∈ dom ⁡ F → A F B F C = V
16 14 15 nsyl5 ⊢ ¬ A ∈ S ∧ B ∈ S ∧ C ∈ S → A F B F C = V
17 1 eleq2i ⊢ A B F C ∈ dom ⁡ F ↔ A B F C ∈ S × S
18 opelxp ⊢ A B F C ∈ S × S ↔ A ∈ S ∧ B F C ∈ S
19 17 18 bitri ⊢ A B F C ∈ dom ⁡ F ↔ A ∈ S ∧ B F C ∈ S
20 aovvdm ⊢ B F C ∈ S → B C ∈ dom ⁡ F
21 1 eleq2i ⊢ B C ∈ dom ⁡ F ↔ B C ∈ S × S
22 opelxp ⊢ B C ∈ S × S ↔ B ∈ S ∧ C ∈ S
23 21 22 bitri ⊢ B C ∈ dom ⁡ F ↔ B ∈ S ∧ C ∈ S
24 3anass ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S ↔ A ∈ S ∧ B ∈ S ∧ C ∈ S
25 24 biimpri ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S → A ∈ S ∧ B ∈ S ∧ C ∈ S
26 25 a1d ⊢ A ∈ S ∧ B ∈ S ∧ C ∈ S → A B F C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
27 26 expcom ⊢ B ∈ S ∧ C ∈ S → A ∈ S → A B F C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
28 23 27 sylbi ⊢ B C ∈ dom ⁡ F → A ∈ S → A B F C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
29 20 28 syl ⊢ B F C ∈ S → A ∈ S → A B F C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
30 29 impcom ⊢ A ∈ S ∧ B F C ∈ S → A B F C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
31 19 30 sylbi ⊢ A B F C ∈ dom ⁡ F → A B F C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
32 31 pm2.43i ⊢ A B F C ∈ dom ⁡ F → A ∈ S ∧ B ∈ S ∧ C ∈ S
33 ndmaov ⊢ ¬ A B F C ∈ dom ⁡ F → A F B F C = V
34 32 33 nsyl5 ⊢ ¬ A ∈ S ∧ B ∈ S ∧ C ∈ S → A F B F C = V
35 16 34 eqtr4d ⊢ ¬ A ∈ S ∧ B ∈ S ∧ C ∈ S → A F B F C = A F B F C