Metamath Proof Explorer


Theorem nfafv

Description: Bound-variable hypothesis builder for function value, analogous to nffv . To prove a deduction version of this analogous to nffvd is not easily possible because a deduction version of nfdfat cannot be shown easily. (Contributed by Alexander van der Vekens, 26-May-2017)

Ref Expression
Hypotheses nfafv.1 ⊢ Ⅎ _ x F
nfafv.2 ⊢ Ⅎ _ x A
Assertion nfafv ⊢ Ⅎ _ x F ''' A

Proof

Step Hyp Ref Expression
1 nfafv.1 ⊢ Ⅎ _ x F
2 nfafv.2 ⊢ Ⅎ _ x A
3 dfafv2 ⊢ F ''' A = if F defAt A F ⁡ A V
4 1 2 nfdfat ⊢ Ⅎ x F defAt A
5 1 2 nffv ⊢ Ⅎ _ x F ⁡ A
6 nfcv ⊢ Ⅎ _ x V
7 4 5 6 nfif ⊢ Ⅎ _ x if F defAt A F ⁡ A V
8 3 7 nfcxfr ⊢ Ⅎ _ x F ''' A