Metamath Proof Explorer


Theorem nndvdslegcd

Description: A positive integer which divides both positive operands of the gcd operator is bounded by it. (Contributed by AV, 9-Aug-2020)

Ref Expression
Assertion nndvdslegcd ⊢ K ∈ ℕ ∧ M ∈ ℕ ∧ N ∈ ℕ → K ∥ M ∧ K ∥ N → K ≤ M gcd N

Proof

Step Hyp Ref Expression
1 nnz ⊢ K ∈ ℕ → K ∈ ℤ
2 nnz ⊢ M ∈ ℕ → M ∈ ℤ
3 nnz ⊢ N ∈ ℕ → N ∈ ℤ
4 1 2 3 3anim123i ⊢ K ∈ ℕ ∧ M ∈ ℕ ∧ N ∈ ℕ → K ∈ ℤ ∧ M ∈ ℤ ∧ N ∈ ℤ
5 nnne0 ⊢ M ∈ ℕ → M ≠ 0
6 5 neneqd ⊢ M ∈ ℕ → ¬ M = 0
7 6 3ad2ant2 ⊢ K ∈ ℕ ∧ M ∈ ℕ ∧ N ∈ ℕ → ¬ M = 0
8 7 intnanrd ⊢ K ∈ ℕ ∧ M ∈ ℕ ∧ N ∈ ℕ → ¬ M = 0 ∧ N = 0
9 dvdslegcd ⊢ K ∈ ℤ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ ¬ M = 0 ∧ N = 0 → K ∥ M ∧ K ∥ N → K ≤ M gcd N
10 4 8 9 syl2anc ⊢ K ∈ ℕ ∧ M ∈ ℕ ∧ N ∈ ℕ → K ∥ M ∧ K ∥ N → K ≤ M gcd N