Metamath Proof Explorer


Theorem ntrclselnel2

Description: If (pseudo-)interior and (pseudo-)closure functions are related by the duality operator then there is an equivalence between membership in interior of the complement of a set and non-membership in the closure of the set. (Contributed by RP, 28-May-2021)

Ref Expression
Hypotheses ntrcls.o ⊢ O = i ∈ V ⟼ k ∈ 𝒫 i 𝒫 i ⟼ j ∈ 𝒫 i ⟼ i ∖ k ⁡ i ∖ j
ntrcls.d ⊢ D = O ⁡ B
ntrcls.r ⊢ φ → I D K
ntrcls.x ⊢ φ → X ∈ B
ntrcls.s ⊢ φ → S ∈ 𝒫 B
Assertion ntrclselnel2 ⊢ φ → X ∈ I ⁡ B ∖ S ↔ ¬ X ∈ K ⁡ S

Proof

Step Hyp Ref Expression
1 ntrcls.o ⊢ O = i ∈ V ⟼ k ∈ 𝒫 i 𝒫 i ⟼ j ∈ 𝒫 i ⟼ i ∖ k ⁡ i ∖ j
2 ntrcls.d ⊢ D = O ⁡ B
3 ntrcls.r ⊢ φ → I D K
4 ntrcls.x ⊢ φ → X ∈ B
5 ntrcls.s ⊢ φ → S ∈ 𝒫 B
6 1 2 3 ntrclsnvobr ⊢ φ → K D I
7 1 2 6 4 5 ntrclselnel1 ⊢ φ → X ∈ K ⁡ S ↔ ¬ X ∈ I ⁡ B ∖ S
8 7 con2bid ⊢ φ → X ∈ I ⁡ B ∖ S ↔ ¬ X ∈ K ⁡ S