Metamath Proof Explorer


Theorem obsip

Description: The inner product of two elements of an orthonormal basis. (Contributed by Mario Carneiro, 23-Oct-2015)

Ref Expression
Hypotheses isobs.v ⊢ V = Base W
isobs.h ⊢ , ˙ = ⋅ 𝑖 ⁡ W
isobs.f ⊢ F = Scalar ⁡ W
isobs.u ⊢ 1 ˙ = 1 F
isobs.z ⊢ 0 ˙ = 0 F
Assertion obsip ⊢ B ∈ OBasis ⁡ W ∧ P ∈ B ∧ Q ∈ B → P , ˙ Q = if P = Q 1 ˙ 0 ˙

Proof

Step Hyp Ref Expression
1 isobs.v ⊢ V = Base W
2 isobs.h ⊢ , ˙ = ⋅ 𝑖 ⁡ W
3 isobs.f ⊢ F = Scalar ⁡ W
4 isobs.u ⊢ 1 ˙ = 1 F
5 isobs.z ⊢ 0 ˙ = 0 F
6 eqid ⊢ ocv ⁡ W = ocv ⁡ W
7 eqid ⊢ 0 W = 0 W
8 1 2 3 4 5 6 7 isobs ⊢ B ∈ OBasis ⁡ W ↔ W ∈ PreHil ∧ B ⊆ V ∧ ∀ x ∈ B ∀ y ∈ B x , ˙ y = if x = y 1 ˙ 0 ˙ ∧ ocv ⁡ W ⁡ B = 0 W
9 8 simp3bi ⊢ B ∈ OBasis ⁡ W → ∀ x ∈ B ∀ y ∈ B x , ˙ y = if x = y 1 ˙ 0 ˙ ∧ ocv ⁡ W ⁡ B = 0 W
10 9 simpld ⊢ B ∈ OBasis ⁡ W → ∀ x ∈ B ∀ y ∈ B x , ˙ y = if x = y 1 ˙ 0 ˙
11 oveq1 ⊢ x = P → x , ˙ y = P , ˙ y
12 eqeq1 ⊢ x = P → x = y ↔ P = y
13 12 ifbid ⊢ x = P → if x = y 1 ˙ 0 ˙ = if P = y 1 ˙ 0 ˙
14 11 13 eqeq12d ⊢ x = P → x , ˙ y = if x = y 1 ˙ 0 ˙ ↔ P , ˙ y = if P = y 1 ˙ 0 ˙
15 oveq2 ⊢ y = Q → P , ˙ y = P , ˙ Q
16 eqeq2 ⊢ y = Q → P = y ↔ P = Q
17 16 ifbid ⊢ y = Q → if P = y 1 ˙ 0 ˙ = if P = Q 1 ˙ 0 ˙
18 15 17 eqeq12d ⊢ y = Q → P , ˙ y = if P = y 1 ˙ 0 ˙ ↔ P , ˙ Q = if P = Q 1 ˙ 0 ˙
19 14 18 rspc2v ⊢ P ∈ B ∧ Q ∈ B → ∀ x ∈ B ∀ y ∈ B x , ˙ y = if x = y 1 ˙ 0 ˙ → P , ˙ Q = if P = Q 1 ˙ 0 ˙
20 10 19 syl5com ⊢ B ∈ OBasis ⁡ W → P ∈ B ∧ Q ∈ B → P , ˙ Q = if P = Q 1 ˙ 0 ˙
21 20 3impib ⊢ B ∈ OBasis ⁡ W ∧ P ∈ B ∧ Q ∈ B → P , ˙ Q = if P = Q 1 ˙ 0 ˙