Metamath Proof Explorer


Theorem ofc12

Description: Function operation on two constant functions. (Contributed by Mario Carneiro, 28-Jul-2014)

Ref Expression
Hypotheses ofc12.1 ⊢ φ → A ∈ V
ofc12.2 ⊢ φ → B ∈ W
ofc12.3 ⊢ φ → C ∈ X
Assertion ofc12 ⊢ φ → A × B R f A × C = A × B R C

Proof

Step Hyp Ref Expression
1 ofc12.1 ⊢ φ → A ∈ V
2 ofc12.2 ⊢ φ → B ∈ W
3 ofc12.3 ⊢ φ → C ∈ X
4 2 adantr ⊢ φ ∧ x ∈ A → B ∈ W
5 3 adantr ⊢ φ ∧ x ∈ A → C ∈ X
6 fconstmpt ⊢ A × B = x ∈ A ⟼ B
7 6 a1i ⊢ φ → A × B = x ∈ A ⟼ B
8 fconstmpt ⊢ A × C = x ∈ A ⟼ C
9 8 a1i ⊢ φ → A × C = x ∈ A ⟼ C
10 1 4 5 7 9 offval2 ⊢ φ → A × B R f A × C = x ∈ A ⟼ B R C
11 fconstmpt ⊢ A × B R C = x ∈ A ⟼ B R C
12 10 11 eqtr4di ⊢ φ → A × B R f A × C = A × B R C